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Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

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Nội dung chính
    Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.Answer (Detailed Solution Below)The correct option is C 151To find the least number which is divisible by 12, 16 ,24 and 36, we need to find L.C.M. of these numbers. 212,16,24,3626,8,12,1823,4,6,923,2,3,933,1,3,931,1,1,31,1,1,1 L.C.M. of 12, 16, 24, 36 =2×2×2×2×3×3=144 Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151What is the least number which when divided by 12 16 24 36 leaves a remainder 7 in each case?What is the least number which when divided by 12 20 and 24 leaves in each case a remainder of 8?What will be the least number which when divided by 12 15 18 and 24 leaves a remainder of 7 in each case?Which is the least number which when divided by 12 and 16 leave the same remainder?

SSC CGL Tier 2 Quant Previous Paper 3 (Held On: 18 November 2022)

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366634384364

Answer (Detailed Solution Below)

Option 4 : 364

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Concept Used-

The least number which is divisible by several numbers is the LCM of such numbers.

Calculation-

The least number which is divisible by 12, 18, 24 and 30 = LCM of 12, 18, 24 and 30

⇒ 360

Now the least number which leaves remainder as 4 when divided by 12, 18, 24 and 30 = 360 + 4

⇒ 364

Now, 364 is divisible by 7.

∴ 364 is the required number.

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Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case.

Solution

We first find the LCM of 12, 16, 24, and 36 as follows:

What is the least number which when divided by 12 24 and 30 leaves a remainder 7 in each case?

Thus, LCM = 2 × 2 × 2 × 2 × 3 × 3 = 144

144 is the least number which when divided by the given numbers will leave remainder 0 in each case. But we need the least number that leaves remainder 7in each case.
Therefore, the required number is 7 more than 144.

The required least number = 144 + 7 = 151.

Concept: Lowest Common Multiple

  Is there an error in this question or solution?

Correct Answer - Option 4 : 364

Concept Used-

The least number which is divisible by several numbers is the LCM of such numbers.

Calculation-

The least number which is divisible by 12, 18, 24 and 30 = LCM of 12, 18, 24 and 30

⇒ 360

Now the least number which leaves remainder as 4 when divided by 12, 18, 24 and 30 = 360 + 4

⇒ 364

Now, 364 is divisible by 7.

∴ 364 is the required number.

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Solution

The correct option is C 151To find the least number which is divisible by 12, 16 ,24 and 36, we need to find L.C.M. of these numbers. 212,16,24,3626,8,12,1823,4,6,923,2,3,933,1,3,931,1,1,31,1,1,1 L.C.M. of 12, 16, 24, 36 =2×2×2×2×3×3=144 Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151

What is the least number which when divided by 12 16 24 36 leaves a remainder 7 in each case?

Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151.

What is the least number which when divided by 12 20 and 24 leaves in each case a remainder of 8?

Calculation: Least number which is divisible by all given number is LCM of all numbers. ∴ The required number is 128.

What will be the least number which when divided by 12 15 18 and 24 leaves a remainder of 7 in each case?

∴ 364 is the required number.

Which is the least number which when divided by 12 and 16 leave the same remainder?

The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is : - GKToday. = 48 – 7 = 41. Hence option [C] is correct answer. Tải thêm tài liệu liên quan đến nội dung bài viết What is the least number which when divided by 12 24 and 30 leaves a remainder 7 in each case?

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